7p^2+4p=2

Solution for 7p^2+4p=2 equation:

7p^2+4p=2

We move all terms to the left:

7p^2+4p-(2)=0

a = 7; b = 4; c = -2;
Δ = b2-4ac
Δ = 42-4·7·(-2)
Δ = 72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{72}=\sqrt{36*2}=\sqrt{36}*\sqrt{2}=6\sqrt{2}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-6\sqrt{2}}{2*7}=\frac{-4-6\sqrt{2}}{14}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+6\sqrt{2}}{2*7}=\frac{-4+6\sqrt{2}}{14}
$